
PTB 9th Class Physics Chapter 1 Solved Questions and Numericals Problems
Sunday, December 30, 2012 Category: NotesView and Download the solved questions, solved numerical problems or 9th Class Physics notes of Chapter 1 “Physical Quantities and Measurement” of Punjab Textbook Board. These 9th class physics notes of 1st Chapter are according to the new syllabus (2013) of Punjab Boards including Lahore Board, Gujranwala Board, Sahiwal Board, Rawalpindi Board, Faisalabad Board, Multan Board, Bahawalpur Board, Federal Board, DG Khan Board and Sargodha Board. Students of 9th Class of all these board can facilitate from the physics notes given below. You can also download 9th Class Physics Chapter 1 Solved Questions and Numericals Problems.
Unit 1: Physical Quantities and Measurements
By studying this chapter students will be able to: Describe the crucial role of Physics in Science, Technology and Society. Explain with examples that Science is based on physical quantities which consist of numerical magnitude and a unit. Differentiate between base and derived physical quantities. list the seven units of System International (SI) alongwith their symbols and physical quantities (standard definitions of SI units are not required). Interconvert the prefixes and their symbols to indicate multiples and sub-multiples for both base and derived units. Write the answer in scientific notation in measurements and calculations. Describe the working of Vernier Callipers and screw gauge for measuring length. Identify and explain the limitations of measuring instruments such as metre rule, Vernier Callipers and screw gauge. Describe the need using significant figures for recording and stating results in the laboratory.
9th Class Physics Chapter 1 Short Question Answers
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9th Class Physics Chapter 1 Solved Numericals
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Correction and Comments about Numericals and Short Question Answers
- Short Question 1.8
Problem: Wrong answer given in notes.
Correct Answer: It is the measurement or value that an instrument shows when it should be showing zero. - Short Question 1.9
Problem: Wrong answer given in notes.
Correct Answer: By knowing the zero error, necessary correction can be made to find correct measurement. Otherwise our reading will be incorrect. - Numerical 1.7
Problem : Wrong values of pitch of the screw guage(0.1mm) and number of division(100).
Correction: The vale of pitch of the screw should be 0.5mm and number of divisions should be 50 according to the question. There is no change in answer, it remains the same.
Click 9th Class Physics Notes for other chapter’s notes
These solved numerical problems and question answer are explain properly and we hope that students will not find any difficult or confusion in these notes. But if students have any type of question or query regarding 9th Class Physics Notes, Solved Question Answers and Solved Numerical problems, then they can ask us by commenting below in the comment section.
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please upload video lecture of 9th and metric class practicals
Kindly guide me about the quick quiz Q2!
sir ye ab new tab mein open he nahi hota or nahi full screen mein plz repair
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sir plz ap mujy 9 class ki physics k chapter 1 ki mini exercises aur quik quize b send kr den?
i need a question answers physics of class 9
i need 10th class chemistry papers of 2013
i need a 9 class physics numerical soulation plz sir
yr muje 4th bi monthly ka important bata do plzzzzzzzzz
tell me about chapter 1 problm 1.7 …… too much confusing…… pitch of scre is .5mm .no ov divisns is 50….. simply divide pich by no ov divisn…. 4m ur notes i cant understnd it….
Yes you are right, there is little mistake in our notes.
guide us about quick quizes/…….
What do u want to know?
i want to know the nam ov authr of ths notes
Why do you want to know?
plzzzzzzzzzz tell me …..
plzzzzzz guide us about quick quizes of 9th class……… and i found mistakes in chapter 3 mcq and 1 short qustn……. correct it…… nd thnxxxxxxx 4 great notes…… Allah bless u
Kindly tell the question numbers of the incorrect answers.
chapter 3 qustn 3.8 tentn in roop………. its anz iz nt 100….
if it iz 100 then plzzzzzzzzzz tell how…… i discuss this qustn 2 my teachrz….. nd finally i found correct ans that iz 200
It is 100N, let me explain it by an example. Consider a block weighing 100N attached to a string, the other end of the string is attached to a roof, now the block is stationery it means that there is force equal and opposite to the weight of the box (according to Newton’s third law of motion). So the tension in the string is 100N equal to the weight of the box.
no its iz 200 newtn…….. tentin is due to both of forces that iz 200n……. 3 phd doctrs reply me 200 netn/……..
Don’t just give answers, give explanation. Tell your doctors the explanation I have given you.
tentn is stess which is due to both of forces either they are oposite sides……. that is 200 netn
plzzzzzzzzzzzzzz ap is ko again search kry or discuss kry apny teachrz sy……
2 forces lag rhi 100 newtn ki ……… mjy ap k anz ki samaj nai i
forces 100 100 ki dono sides py to????????????????????? m toooooooooo much confusedddddd……. plzzzzzzzzzzzzzzzzzz guide me…………..
oky
Madiha admin sahi keh rahay hain. Jab koi box kisi support se hang hota hai tab bhi us ki string pe dono taraf se 100N ki opposite force lag rahi hoti hai lekin ham tension box k weight k equal letay hain. Haan agar dono forces same direction mai hoti tu tab 200N tension hoti.